Thetwilightsagabreakingdawnpart2hindidubbedtorrent

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Thetwilightsagabreakingdawnpart2hindidubbedtorrent





 
 
 
 
 
 
 

Thetwilightsagabreakingdawnpart2hindidubbedtorrent

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This entry was posted on April 28, 2017 at 11:37 AM and is filed under Windows. You can follow any responses to this entry through the RSS 2.0 feed.
You can leave a response, or trackback from your own site.Q:

Easy way to get the oldest row for each group of day/month/year?

When using the EXCEPT operator, I can get all the rows that are NOT in one query. However, when I do cross joins, I get duplicate rows.
As a result, my final result is a bit bloated with large number of rows with identical data (duplicates).
How would I get the oldest row for each group of a series of columns?
Example

Date, Id, Charts, Sales
2017-10-20, 1, Charts, Sales
2017-10-20, 1, Charts, Sales
2017-10-20, 1, Charts, Sales
2017-10-20, 1, Sales
2017-10-20, 1, Sales
2017-10-21, 1, Sales
2017-10-21, 1, Sales
2017-10-22, 2, Charts, Sales
2017-10-22, 2, Charts, Sales
2017-10-22, 2, Charts, Sales

Would like to get

Date, Id, Charts, Sales
2017-10-20, 1, Charts, Sales
2017-10-21, 1, Sales
2017-10-22, 2, Charts, Sales

A:

You can use union all here:
select Date, Id, Charts, Sales
from (
select
date(day), Id,
max(date(day)) over(partition by Id) as d1,
Charts, Sales
from yourtable
) t1
union all
select date(day), Id,
max(case when to_char(date(day), ‘YYYY-MM-DD’) =
to_char(max(day), ‘

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